SQL开发知识：SQLserver中cube：多维数据集实例详解

1、cube:生成多维数据集，包含各维度可能组合的交叉表格，使用with 关键字连接 with cube

根据需要使用union all 拼接

判断 某一列的null值来自源数据还是 cube 使用GROUPING关键字

GROUPING([档案号]) = 1 ： null值来自cube（代表所有的档案号）
GROUPING([档案号]) = 0 ： null值来自源数据

举例：

SELECT * INTO ##GET
FROM
(SELECT *
FROM ( SELECT
CASE
WHEN (GROUPING([档案号]) = 1) THEN
‘合计’
ELSE [档案号]
END AS ‘档案号’,
CASE
WHEN (GROUPING([系列]) = 1) THEN
‘合计’
ELSE [系列]
END AS ‘系列’,
CASE
WHEN (GROUPING([店长]) = 1) THEN
‘合计’
ELSE [店长]
END AS ‘店长’, SUM (剩余次数) AS ‘总剩余’,
CASE
WHEN (GROUPING([店名]) = 1) THEN
‘合计’
ELSE [店名]
END AS ‘店名’
FROM ##PudianCard
GROUP BY [档案号], [店名], [店长], [系列]
WITH cube
HAVING GROUPING([店名]) != 1
AND GROUPING([档案号]) = 1 –AND GROUPING([系列]) = 1 ) AS M
UNION
ALL
(SELECT *
FROM ( SELECT
CASE
WHEN (GROUPING([档案号]) = 1) THEN
‘合计’
ELSE [档案号]
END AS ‘档案号’,
CASE
WHEN (GROUPING([系列]) = 1) THEN
‘合计’
ELSE [系列]
END AS ‘系列’,
CASE
WHEN (GROUPING([店长]) = 1) THEN
‘合计’
ELSE [店长]
END AS ‘店长’, SUM (剩余次数) AS ‘总剩余’,
CASE
WHEN (GROUPING([店名]) = 1) THEN
‘合计’
ELSE [店名]
END AS ‘店名’
FROM ##PudianCard
GROUP BY [档案号], [店名], [店长], [系列]
WITH cube
HAVING GROUPING([店名]) != 1
AND GROUPING([店长]) != 1 ) AS P )
UNION
ALL
(SELECT *
FROM ( SELECT
CASE
WHEN (GROUPING([档案号]) = 1) THEN
‘合计’
ELSE [档案号]
END AS ‘档案号’,
CASE
WHEN (GROUPING([系列]) = 1) THEN
‘合计’
ELSE [系列]
END AS ‘系列’,
CASE
WHEN (GROUPING([店长]) = 1) THEN
‘合计’
ELSE [店长]
END AS ‘店长’, SUM (剩余次数) AS ‘总剩余’,
CASE
WHEN (GROUPING([店名]) = 1) THEN
‘合计’
ELSE [店名]
END AS ‘店名’
FROM ##PudianCard
GROUP BY [档案号], [店名], [店长], [系列]
WITH cube
HAVING GROUPING([店名]) != 1
AND GROUPING([店长]) != 1 ) AS W )
UNION
ALL
(SELECT *
FROM ( SELECT
CASE
WHEN (GROUPING([档案号]) = 1) THEN
‘合计’
ELSE [档案号]
END AS ‘档案号’,
CASE
WHEN (GROUPING([系列]) = 1) THEN
‘合计’
ELSE [系列]
END AS ‘系列’,
CASE
WHEN (GROUPING([店长]) = 1) THEN
‘合计’
ELSE [店长]
END AS ‘店长’, SUM (剩余次数) AS ‘总剩余’,
CASE
WHEN (GROUPING([店名]) = 1) THEN
‘合计’
ELSE [店名]
END AS ‘店名’
FROM ##PudianCard
GROUP BY [档案号], [店名], [店长], [系列]
WITH cube
HAVING GROUPING([店名]) = 1
AND GROUPING([店长]) = 1
AND GROUPING([档案号]) = 1 ) AS K ) ) AS T